Find the value of x for \(\frac{2 + 2x}{3} - 2 \geq \frac{4x - 6}{5}\)
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Correct Answer: Option C
Explanation:
\(\frac{2 + 2x}{3} - 2 \geq \frac{4x - 6}{5}\)
\(\frac{2 + 2x - 6}{3} \geq \frac{4x - 6}{5}\)
\(\frac{2x - 4}{3} \geq \frac{4x - 6}{5}\)
\(5(2x - 4) \geq 3(4x - 6)\)
\(10x - 20 \geq 12x - 18\)
\(10x - 12x \geq -18 + 20\)
\(-2x \geq 2\)
\(x \leq -1\)
\(\frac{2 + 2x}{3} - 2 \geq \frac{4x - 6}{5}\)
\(\frac{2 + 2x - 6}{3} \geq \frac{4x - 6}{5}\)
\(\frac{2x - 4}{3} \geq \frac{4x - 6}{5}\)
\(5(2x - 4) \geq 3(4x - 6)\)
\(10x - 20 \geq 12x - 18\)
\(10x - 12x \geq -18 + 20\)
\(-2x \geq 2\)
\(x \leq -1\)