In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR.
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Correct Answer: Option B
Explanation:
< QSR = 90° (angle in a semi-circle)
\(\therefore\) < SQR = 180° - (90° + 62°)
= 28°
< QSR = 90° (angle in a semi-circle)
\(\therefore\) < SQR = 180° - (90° + 62°)
= 28°