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The weights to the nearest kilogram, of a group of 50 students in a College of ...

The weights to the nearest kilogram, of a group of 50 students in a College of Technology are given below:
65, 70, 60, 46, 51, 55, 59, 63, 68, 53, 47, 53, 72, 53, 67, 62, 64, 70, 57, 56, 73, 56, 48, 51, 58, 63, 65, 62, 49, 64, 53, 59, 63, 50, 48, 72, 67, 56, 61, 64, 66, 52, 49, 62, 71, 58, 53, 69, 63, 59.
(a) Prepare a grouped fraquency table with class intervals 45 - 49, 50 - 54, 55 - 59 etc.
(b) Using an assumed mean of 62 or otherwise, calculate the mean and standard deviation of the grouped data, correct to one decimal place.
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    Correct Answer: Option n
    Explanation:
    (a)
    Class Interval Tally Freq
    45 - 49 |||| | 6
    50 - 54 |||| |||| 9
    55 - 59 |||| |||| 10
    60 - 64 |||| |||| || 12
    65 - 69 |||| || 7
    70 - 74 |||| | 6



    (b)
    ClassInterval Mid-value(x) x - 62 \((x - 62)^{2}\) \(f\) \(f(x - 62)\) \(f(x - 62)^{2}\)
    45 - 49 47 -15 225 6 -90 1350
    50 - 54 52 -10 100 9 -90 900
    55 - 59 57 -5 25 10 -50 250
    60 - 64 62 0 0 12 0 0
    65 - 69 67 5 25 7 35 175
    70 - 74 72 10 100 6 60 600
    \(\sum\) 50 -135 3275



    \(Mean (\bar{x}) = A + \frac{\sum f(x - A)}{\sum f}\)
    = \(62 + \frac{-135}{50}\)
    = \(62 - 2.7 = 49.3\)
    Standard deviation = \(\sqrt{\frac{\sum f(x - A)}{\sum f}}\)
    = \(\sqrt{\frac{3275}{50}}\)
    = \(\sqrt{65.5}\)
    = \(8.093 \approxeq 8.1\) (to 1 decimal place)

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