Simplify: log6 + log2 - log12
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Correct Answer: Option C
Explanation:
log 6 + log 2 - log 12
= \(\log (\frac{6 \times 2}{12})\)
= \(\log 1\)
= 0
log 6 + log 2 - log 12
= \(\log (\frac{6 \times 2}{12})\)
= \(\log 1\)
= 0