If events X and Y are mutually exclusive, . P(X) = 1/3 and P(Y) = 2/5, P(X∩Y) is
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
P(X \(\cap\) Y) = \(\frac{1}{3} \times \frac{2}{5}\)
= \(\frac{2}{15}\)
P(X \(\cap\) Y) = \(\frac{1}{3} \times \frac{2}{5}\)
= \(\frac{2}{15}\)