A man bought 5 reams of duplicating paper, each of which are supposed to contain 480 sheets. The actual number of sheets in the packets were : 435, 420, 405, 415 and 440.
(a) Calculate, correct to the nearest whole number, the percentage error for the packets of paper;
(b) If the agreed price for a full ream was N35.00, find, correct to the nearest naira, the amount by which the buyer was cheated.
(a) Calculate, correct to the nearest whole number, the percentage error for the packets of paper;
(b) If the agreed price for a full ream was N35.00, find, correct to the nearest naira, the amount by which the buyer was cheated.
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Correct Answer: Option n
Explanation:
(a) Sheets expected from 5 packets = \(480 \times 5 = 2400\)
Actual sheet contained in the packets = \(435 + 420 + 405 + 415 + 440 = 2115\)
Error in supply = 2400 - 2115 = 285 sheets.
\(\therefore\) Percentage error = \(\frac{285}{2400} \times 100% = 11.875%\)
\(\approxeq 12%\)
(b) If 1 packet = 480 sheets cost N35.00
\(\therefore \text{2400 sheets cost } \frac{2400}{480} \times N35.00 = N175.00\)
Amount of buyer was cheated = \(\frac{Error \times N175}{\text{Expected no of sheets}}\)
\(\frac{N285 \times 175}{2400} = N20.78\)
The buyer was cheated by N21 to the nearest naira.
(a) Sheets expected from 5 packets = \(480 \times 5 = 2400\)
Actual sheet contained in the packets = \(435 + 420 + 405 + 415 + 440 = 2115\)
Error in supply = 2400 - 2115 = 285 sheets.
\(\therefore\) Percentage error = \(\frac{285}{2400} \times 100% = 11.875%\)
\(\approxeq 12%\)
(b) If 1 packet = 480 sheets cost N35.00
\(\therefore \text{2400 sheets cost } \frac{2400}{480} \times N35.00 = N175.00\)
Amount of buyer was cheated = \(\frac{Error \times N175}{\text{Expected no of sheets}}\)
\(\frac{N285 \times 175}{2400} = N20.78\)
The buyer was cheated by N21 to the nearest naira.