A sector of a circle of radius 9cm subtends angle 120° at the centre of the circle.
Find the area of the sector to the nearest cm\(^2\) [Take π = 22/7]
Find the area of the sector to the nearest cm\(^2\) [Take π = 22/7]
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Correct Answer: Option C
Explanation:
Area of a sector = θ/360 x πr\(^2\)
= 120/360 x 22/7 x 81/1
= 84.86 cm\(^2\)
\(\approxeq\) 85cm\(^2\) (to the nearest cm)
Area of a sector = θ/360 x πr\(^2\)
= 120/360 x 22/7 x 81/1
= 84.86 cm\(^2\)
\(\approxeq\) 85cm\(^2\) (to the nearest cm)