Evaluate \( \frac{27^{\frac{1}{3}}}{16^{-\frac{1}{4}}} \)
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Correct Answer: Option A
Explanation:
\(\frac{27^{\frac{1}{3}}}{16^{-\frac{1}{4}}} \)
= \(\frac{(3^3)^{\frac{1}{3}}}{(2^4)^{-\frac{1}{4}}}\)
= \(\frac{3}{2^{-1}}\)
= 6
\(\frac{27^{\frac{1}{3}}}{16^{-\frac{1}{4}}} \)
= \(\frac{(3^3)^{\frac{1}{3}}}{(2^4)^{-\frac{1}{4}}}\)
= \(\frac{3}{2^{-1}}\)
= 6