Find the quadratic equation whose roots are 3 and \(\frac{2}{3}\).
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Correct Answer: Option E
Explanation:
x = 3; x = \(\frac{2}{3}\).
(x - 3)(x - \(\frac{2}{3}\)) = 0
\(x^2 - \frac{2x}{3} - 3x + 2 = 0\)
\(x^2 - \frac{11x}{3} + 2 = 0\)
\(3x^2 - 11x + 6 = 0\)
x = 3; x = \(\frac{2}{3}\).
(x - 3)(x - \(\frac{2}{3}\)) = 0
\(x^2 - \frac{2x}{3} - 3x + 2 = 0\)
\(x^2 - \frac{11x}{3} + 2 = 0\)
\(3x^2 - 11x + 6 = 0\)