Which of the following could be the inequality illustrated in the sketch graph above?
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Correct Answer: Option B
Explanation:
Gradient of the line = \(\frac{3 - 0}{0 - 1}\)
= -3
y = -3x + b.
Using (1,0), we have
0 = -3(1) + b
0 = -3 + b
b = 3
y = -3x + 3
\(\therefore\) The graph illustrates y \(\leq\) -3x + 3.
Gradient of the line = \(\frac{3 - 0}{0 - 1}\)
= -3
y = -3x + b.
Using (1,0), we have
0 = -3(1) + b
0 = -3 + b
b = 3
y = -3x + 3
\(\therefore\) The graph illustrates y \(\leq\) -3x + 3.