In the diagram above, PQ is parallel to TU, ∠PQR = 50°, ∠QRS = 86° and ∠STU = 64°. Calculate the value of x.
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Correct Answer: Option D
Explanation:
y = 86° - 50° [Alternate ∠s are equal]
y = 86° - 50° = 36°
a = y = 36° [Alternate ∠s]; b = 64° [Alternate ∠s;]
x = a + b = (36° + 64°)
=100°
y = 86° - 50° [Alternate ∠s are equal]
y = 86° - 50° = 36°
a = y = 36° [Alternate ∠s]; b = 64° [Alternate ∠s;]
x = a + b = (36° + 64°)
=100°