In ΔABC above, BC is produced to D, /AB/ = /AC/ and ∠BAC = 50o. Find ∠ACD

In ΔABC above, BC is produced to D, /AB/ = /AC/ and ∠BAC = 50^o. Find ∠ACD

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A 50^o
B 60^o
C 65^o
D 100^o
E 115^o

Correct Answer: Option E

Explanation:
ACB = ABC [Base angles of isoceles triangle]
ACB + ABC + 50^o = 180^o[sum of angles in a triangle]
ACB + ABC = 180^o - 50^o = 130^oACB
130^o/2
= 65^o

ACD + ACB = 180^o[sum of ∠s on a straight line]
ACD + 65^o = 180^o
ACD = 180^o - 65^o = 115^o

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In ΔABC above, BC is produced to D, /AB/ = /AC/ and ∠BAC = 50o. Find ∠ACD

Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE

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