The bearing of two points Q and R from a point P are 030° and 120° respectively, lf /PQ/ = 12 m and /PR/ = 5 m, find the distance QR.
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Correct Answer: Option A
Explanation:
x\(^2\) = 12\(^2\) + 5\(^2\)
x\(^2\) = 144 + 25
x\(^2\) = 169
x = \(\sqrt{169}\) = 13m.
x\(^2\) = 12\(^2\) + 5\(^2\)
x\(^2\) = 144 + 25
x\(^2\) = 169
x = \(\sqrt{169}\) = 13m.