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Wednesday, 01 April 2026
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A student found the approximate value of 0.02548 correct to two places of decimal ...

A student found the approximate value of 0.02548 correct to two places of decimal instead of two significant figures. Find the percentage error.
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  • A 0%
  • B 131/3%
  • C 15 5/13%
  • D 2/3%
  • E 20%
Correct Answer: Option E
Explanation:
0.02548 \(\approxeq\) 0.03 (to 2 decimal places)
0.02548 \(\approxeq\) 0.025 (2 sig. figs)
Error = 0.03 - 0.025
= 0.005
% error = \(\frac{0.005}{0.025} \times 100%\)
= 20%

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