O is the centre of the circle PQRS. PR and QS intersect at T POR is a diameter, ∠PQT = 42o and ∠QTR = 64o; Find ∠QRT
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Correct Answer: Option A
Explanation:
TQR = 90 - 42 = 48o
QRT = 180 - (64 - 48)
= 180 - 112
= 68o
TQR = 90 - 42 = 48o
QRT = 180 - (64 - 48)
= 180 - 112
= 68o