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A group of 11 people can speak either English or French or Both. Seven can speak ...

A group of 11 people can speak either English or French or Both. Seven can speak English and six can speak French. What is the probability that a person chosen at random can speak both English and French?
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  • A \(\frac{2}{11}\)
  • B \(\frac{4}{11}\)
  • C \(\frac{5}{11}\)
  • D \(\frac{11}{13}\)
Correct Answer: Option A
Explanation:
Let the number of people that speak both English and French = x
Then (7 - x) + x + (6 - x) = 11
13 - x = 11 \(\implies\) x = 2.
\(\therefore\) P(picking a person that speaks both languages) = 2/11

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