(a) If \(\varepsilon\) is the set \({1, 2, 3,..., 19, 20}\) and A, B and C are subsets of \(\varepsilon\) such that A = { multiples of five}, B = {multiples of four} and C = {multiples of three}, list the elements of (i) A ; (ii) B ; (iii) C ;
(b) Find : (i) \(A \cap B\) ; (ii) \(A \cap C\) ; (iii) \(B \cup C\).
(c) Using your results in (b), show that \((A \cap B) \cup (A \cap C) = A \cap (B \cup C)\).
(b) Find : (i) \(A \cap B\) ; (ii) \(A \cap C\) ; (iii) \(B \cup C\).
(c) Using your results in (b), show that \((A \cap B) \cup (A \cap C) = A \cap (B \cup C)\).
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Correct Answer: Option n
Explanation:
(a)(i) A = {5, 10, 15, 20}
(ii) B = {4, 8, 12, 16, 20}
(iii) C = {3, 6, 9, 12, 15, 18}
(b) (i) \(A \cap B = {20}\)
(ii) \(A \cap C = {15}\)
(iii) \(B \cap C = {12}\)
(c) \((A \cap B) \cup (A \cap C) = A \cap (B \cup C)\)
\((A \cap B) \cup (A \cap C) = {15, 20}\)
\(A \cap (B \cup C) = {5, 10, 15, 20} \cap {3, 4, 6, 8, 9, 12, 15, 16, 18, 20}\)
= \({15, 20}\)
\(\therefore (A \cap B) \cup (A \cap C) = A \cap (B \cup C)\)
(a)(i) A = {5, 10, 15, 20}
(ii) B = {4, 8, 12, 16, 20}
(iii) C = {3, 6, 9, 12, 15, 18}
(b) (i) \(A \cap B = {20}\)
(ii) \(A \cap C = {15}\)
(iii) \(B \cap C = {12}\)
(c) \((A \cap B) \cup (A \cap C) = A \cap (B \cup C)\)
\((A \cap B) \cup (A \cap C) = {15, 20}\)
\(A \cap (B \cup C) = {5, 10, 15, 20} \cap {3, 4, 6, 8, 9, 12, 15, 16, 18, 20}\)
= \({15, 20}\)
\(\therefore (A \cap B) \cup (A \cap C) = A \cap (B \cup C)\)