Solve the equation \(3y^2 = 27y\)
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Correct Answer: Option B
Explanation:
\(3y^2 = 27y\\
3y^2 - 27y = 0\\
3y(y - 9) = 0\\
3y = 0 or y - 9 = 0\\
y = 0 or y = 9\\
y = 0 or 9\)
\(3y^2 = 27y\\
3y^2 - 27y = 0\\
3y(y - 9) = 0\\
3y = 0 or y - 9 = 0\\
y = 0 or y = 9\\
y = 0 or 9\)