The nth term of a sequence is \(2^{2n-1}\). Which term of the sequence is \(2^9?\)
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Correct Answer: Option C
Explanation:
\(T_{n} = 2^{2n - 1}\)
\(2^{2n - 1} = 2^9\)
\(2n - 1 = 9 \implies 2n = 9 + 1\)
\(2n = 10 \implies n = 5\)
The 5th term = 2\(^9\)
\(T_{n} = 2^{2n - 1}\)
\(2^{2n - 1} = 2^9\)
\(2n - 1 = 9 \implies 2n = 9 + 1\)
\(2n = 10 \implies n = 5\)
The 5th term = 2\(^9\)