If log 2 = 0.3010 and log 2\(^y\) = 1.8062, find; correct to the nearest whole number, the value of y.
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Correct Answer: Option A
Explanation:
\(log2 = 0.3010\hspace{1mm}given\\
log2^y = 1.8062\\
∴ ylog2 = 1.8062\\
y=\frac{1.8062}{logy}=\frac{1.8062}{0.3010}=6\)
\(log2 = 0.3010\hspace{1mm}given\\
log2^y = 1.8062\\
∴ ylog2 = 1.8062\\
y=\frac{1.8062}{logy}=\frac{1.8062}{0.3010}=6\)