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(a) Simplify : \(\frac{\frac{1}{3}c^{2} - \frac{2}{3}cd}{\frac{1}{2}d^{2} - ...



(a) Simplify : \(\frac{\frac{1}{3}c^{2} - \frac{2}{3}cd}{\frac{1}{2}d^{2} - \frac{1}{4}cd}\)
(b)
In the diagram, YPF is a straight line. < XPY = 44°, < MPF = 46°, < XYP = < MFP = 90°, /XY/ = 7cm and /MP/ = 9 cm.
(i) Calculate, correct to 3 significant figures, /XM/ and /YF/ ; (ii) Find < XMP.
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    Correct Answer: Option n
    Explanation:



    (a) \(\frac{\frac{1}{3}c^{2} - \frac{2}{3}cd}{\frac{1}{2}d^{2} - \frac{1}{4}cd}\)
    = \(\frac{\frac{1}{3}c(c - 2d)}{\frac{1}{4}d(2d - c)}\)
    = \(\frac{\frac{1}{3}c (c - 2d)}{-\frac{1}{4}d (c - 2d)}\)
    = \(-\frac{4c}{3d}\)
    (b)(i) In \(\Delta XYP\),
    \(\frac{7}{XP} = \sin 44°\)
    \(XP = \frac{7}{\sin 44}\)
    = \(10.08 cm\)
    < XPM + 44° + 46° = 180°
    < XPM = 90°.
    In \(\Delta XPM\),
    \(XM^{2} = XP^{2} + PM^{2}\)
    \(XM^{2} = (10.08)^{2} + 9^{2}\)
    = \(101.6064 + 81 = 182.6064\)
    \(XM = \sqrt{182.6064}\)
    = \(15.513 cm \approxeq 13.5 cm\)
    In \(\Delta XYP\),
    \(\frac{7}{YP} = \tan 44\)
    \(YP = \frac{7}{\tan 44}\)
    \(YP = 7.249 cm \approxeq 7.2 cm\)
    In \(\Delta MPF\),
    \(\frac{PF}{9} = \cos 46\)
    \(PF = 9 \cos 46 = 6.2519 cm\)
    \(YF = YP + PF = 7.249 + 6.2519\)
    = \(13.5009 cm \approxeq 13.5 cm\)
    (ii)
    \(\frac{10.1}{9} = \tan \theta\)
    \(\tan \theta = 1.122\)
    \(\theta = \tan^{-1} (1.122)\)
    = 48.296°

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