Find the area of a rectangle of length 4cm and whose diagonal is 6cm, (Leave your answer in surd form)
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Correct Answer: Option D
Explanation:
|AB| = 4cm
|BC| = 8cm
In right-angled BAC; |BC|222 8222 64 – 16 = |AC|2 48 = |AC|2 \(AC= \sqrt{48}cm = 4\sqrt{3}cm\)
The area of rectangle = L x B = |AB| x |AC|
= \((4 \times 4\sqrt{3}cm^2)\\
=16\sqrt{3}cm^2\)
|AB| = 4cm
|BC| = 8cm
In right-angled BAC; |BC|222 8222 64 – 16 = |AC|2 48 = |AC|2 \(AC= \sqrt{48}cm = 4\sqrt{3}cm\)
The area of rectangle = L x B = |AB| x |AC|
= \((4 \times 4\sqrt{3}cm^2)\\
=16\sqrt{3}cm^2\)