If \(\left(\frac{1}{4}\right)^{(2-y)} = 1\), find y.
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Correct Answer: Option D
Explanation:
\(2^{-2(2-y)}-x=2^{0}; -4 + 2y = 0\\
2y = 4; y = 2\)
\(2^{-2(2-y)}-x=2^{0}; -4 + 2y = 0\\
2y = 4; y = 2\)