Find the range of values of x for which\(\frac{x+2}{4}-\frac{x+1}{3}>\frac{1}{2}\)
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Correct Answer: Option D
Explanation:
\(\frac{x+2}{4}-\frac{x+1}{3}>\frac{1}{2}\\
\frac{3(x+2)-4(x+1)>6}{12}; 3x + 6 – 4x – 4 > 6\
-x +2>6; -x > 4; x < -4\)
\(\frac{x+2}{4}-\frac{x+1}{3}>\frac{1}{2}\\
\frac{3(x+2)-4(x+1)>6}{12}; 3x + 6 – 4x – 4 > 6\
-x +2>6; -x > 4; x < -4\)