The angle of elevation of the top of a cliff 15 meters high from a landmark is 60o. How far is the landmark from the foot of the cliff? Leave your answer in surd form
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Correct Answer: Option D
Explanation:
\(tan 60^{\circ} = \frac{15}{x} \Rightarrow x = \frac{15}{tan60^{\circ}\\
x = \left(\frac{15}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}\right)m \Rightarrow 5\sqrt{3}m\)
\(tan 60^{\circ} = \frac{15}{x} \Rightarrow x = \frac{15}{tan60^{\circ}\\
x = \left(\frac{15}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}\right)m \Rightarrow 5\sqrt{3}m\)