A machine valued at N20,000 depreciates by 10% every year. What will be the value of the machine at the end of two years?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
D = P(I - \(\frac{R}{100}\))n where P = N20,000; R = 10%, n = 2
D = 20,000(I - \(\frac{10}{100}\))2
= 20000(0.9)2
20,000 x 0.81 = N16,200
D = P(I - \(\frac{R}{100}\))n where P = N20,000; R = 10%, n = 2
D = 20,000(I - \(\frac{10}{100}\))2
= 20000(0.9)2
20,000 x 0.81 = N16,200