If x =3, y = 2 and z = 4 what is the value of \(3x^{2}-2y+z\)
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Correct Answer: Option B
Explanation:
\(3x^{2}-2y+z=3(3)^{2}-2(2)+4=27-4+4=27\)
\(3x^{2}-2y+z=3(3)^{2}-2(2)+4=27-4+4=27\)