If \(8^{x+1}=\frac{1}{4}\), find x
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Correct Answer: Option A
Explanation:
\(8^{x+1}=\frac{1}{4}\\
2^{3(x+1)}=2^{-2}\Rightarrow 3(x+1)=-2\Rightarrow 3x+3=-2\\
3x=-5\Rightarrow x=\frac{5}{3}\)
\(8^{x+1}=\frac{1}{4}\\
2^{3(x+1)}=2^{-2}\Rightarrow 3(x+1)=-2\Rightarrow 3x+3=-2\\
3x=-5\Rightarrow x=\frac{5}{3}\)