If 8x-1 = \(\frac{1}{4}\), find x
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Correct Answer: Option D
Explanation:
8x-1 = \(\frac{1}{4}\)
23(x - 1 = 2-2
3x - 3 = -2
3x = -2 + 3
3x = 1
x = \(\frac{1}{3}\)
8x-1 = \(\frac{1}{4}\)
23(x - 1 = 2-2
3x - 3 = -2
3x = -2 + 3
3x = 1
x = \(\frac{1}{3}\)