The table shows the ages(in years) of twenty children chosen at random from a community. What is the mean age? \(\begin{array}{c|c} Age(years) & 1 & 2 & 3 & 4 & 5 \\ \hline {\text {Number of children}} & 2 & 3 & 5 & 6 & 4 \end{array}\)
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Correct Answer: Option B
Explanation:
Mean(age) = \(\frac{(1 \times 2) + (2 \times 3) + (3 \times 5) + (4 \times 6) + (5 \times 4)}{2 + 3 + 5 + 6 + 4}\)
= \(\frac{2 + 6 + 15 + 24 + 20}{20}\)
= \(\frac{67}{20}\)
= 3.35yrs
Mean(age) = \(\frac{(1 \times 2) + (2 \times 3) + (3 \times 5) + (4 \times 6) + (5 \times 4)}{2 + 3 + 5 + 6 + 4}\)
= \(\frac{2 + 6 + 15 + 24 + 20}{20}\)
= \(\frac{67}{20}\)
= 3.35yrs