Find the value of a if log10 a + log10a2 = 0.9030
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Correct Answer: Option C
Explanation:
Log a + log a2 = 0.9030
log (a x a2) = 0.9030
log a3 = 0.9030
a3 = 10^.9030(antilogarithm table)
a3 = 7.998
a = 3\(\sqrt{7.998}\)
a = 1.6
Log a + log a2 = 0.9030
log (a x a2) = 0.9030
log a3 = 0.9030
a3 = 10^.9030(antilogarithm table)
a3 = 7.998
a = 3\(\sqrt{7.998}\)
a = 1.6