In the diagram, lt; QPR = 60o lt; PQR = 50o lt; QRS = 2xo lt; SRP = 3xo lt; UQP = yo and RS//TU calculate y

In the diagram, < QPR = 60^o
< PQR = 50^o
< QRS = 2x^o
< SRP = 3x^o
< UQP = y^o and RS//TU
calculate y

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A 102^o
B 78^o
C 70^o
D 60^o

Correct Answer: Option A

Explanation:

< RQT = < QRS = 2x (Alternate angles). But in \(\bigtriangleup\) PRQ
50 + 60 + (2x + 3x) = 180^o(Angles in a triangle)
110 + 5x = 180^o
5x = 180^o - 110 = 70^o
x = \(\frac{70}{5}\) = 14^o
Also y + 50 + 2(14) = 180^o
y + 50 + 28 = 180^o
y = 180 - 78
y = 102^o

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In the diagram, lt; QPR = 60o lt; PQR = 50o lt; QRS = 2xo lt; SRP = 3xo lt; UQP = ...

Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE

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