Search SchoolNGR

Saturday, 11 April 2026
Register . Login

(a) Copy and complete the table of values for \(y = 3\sin x + 2\cos x\) for \(0° ...

(a) Copy and complete the table of values for \(y = 3\sin x + 2\cos x\) for \(0° \leq x \leq 360°\).
x 60° 120° 180° 240° 300° 360°
y 2.00 2.00



(b) Using a scale of 2 cm to 60° on x- axis and 2 cm to 1 unit on the y- axis, draw the graph of \(y = 3 \sin x + 2 \cos x\) for \(0° \leq x \leq 360°\).
(c) Use your graph to solve the equation : \(3 \sin x + 2 \cos x = 1.5\).
(d) Find the range of values of x for which \(3\sin x + 2\cos x < -1\).
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
    Correct Answer: Option n
    Explanation:



    (a)
    x 60° 120° 180° 240° 300° 360°
    \(\sin x\) 0 0.8660 0.8660 0 -0.8660 -0.8660 0
    \(\cos x\) 1 0.5 -0.5 -1 -0.5 -0.5 1
    \(3\sin x\) 0 2.598 2.598 0 -2.598 -2.598 0
    \(2\cos x\) 2 1 -1 -2 -1 -1 2
    y 2 3.598 1.598 -2 -3.598 -3.598 2
    y 2.00 3.60 1.60 -2.00 -3.60 -3.60 2.00



    (b)
    (c) From graph, \(x_{1} = 120 + \frac{1}{5} \times 15 = 120 + 3 = 123°\)
    \(x_{2} = 360° - \frac{2}{3} \times 15 = 360 - 10 = 350°\)
    (d) From graph, \(180° - 15 < x < 300 + \frac{3}{5} \times 15\)
    \(165° < x < 300 + 9 = 165° < x < 309°\)

    Share question on: