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solve \(\frac{2x + 1}{6} - \frac{3x - 1}{4}\) = 0

solve \(\frac{2x + 1}{6} - \frac{3x - 1}{4}\) = 0
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  • A 1
  • B \(\frac{1}{5}\)
  • C -\(\frac{1}{5}\)
  • D -1
Correct Answer: Option A
Explanation:
\(\frac{2x + 1}{6} - \frac{3x - 1}{4}\) = 0
\(\frac{4(2n + 1) - 6(3x - 1)}{24}\) = 0
-10x + 10 = 0
-10x = -10
x = \(\frac{-10}{-10}\)
x = 1

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