Find the quadratic equation whose roots are -\(\frac{1}{2}\) and 3
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Correct Answer: Option D
Explanation:
x = \(\frac{-1}{2}\)
x = 3
2x = -1, x = 3; 2x + 1 = 0
x - 3 = 0
(2x + 1)(x - 3) = 0
2x2 - 6x + x - 3 = 0
2x2 - 5x - 3 = 0
x = \(\frac{-1}{2}\)
x = 3
2x = -1, x = 3; 2x + 1 = 0
x - 3 = 0
(2x + 1)(x - 3) = 0
2x2 - 6x + x - 3 = 0
2x2 - 5x - 3 = 0