In the diagram, IG is parallel to JE, JEF = 120o and FHG = 130o, fins the angle marked t - SchoolNGR

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In the diagram, IG is parallel to JE, JEF = 120o and FHG = 130o, fins the angle marked t

In the diagram, IG is parallel to JE, JEF = 120^o and FHG = 130^o, fins the angle marked t

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Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE

A 40^o
B 70^o
C 80^o
D 100^o

Correct Answer: Option B

Explanation:

Now, t + 60^o + 50^o = 180^o
t = 180^o - 110^o
t = 70^o

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