If p = (y : 2y \(\geq\) 6) and Q = (y : y -3 \(\geq\) 4), where y is an integer, find p\(\cap\)Q
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Correct Answer: Option C
Explanation:
p = (y : 2y \(\geq\) 6)
2y \(\leq\) 6
y \(\leq \frac{6}{2}\)
y = \(\leq\) 3
and Q = (y : y -3 \(\geq\) 4)
y - 3 \(\geq\) 4
y \(\geq\) 4 + 3
y \(\geq\) 7
therefore p = {3, 4, 5, 6, 7} and Q = {7, 6, 5, 4, 3....}
P\(\cap\)Q = {3, 4, 5, 6, 7}
p = (y : 2y \(\geq\) 6)
2y \(\leq\) 6
y \(\leq \frac{6}{2}\)
y = \(\leq\) 3
and Q = (y : y -3 \(\geq\) 4)
y - 3 \(\geq\) 4
y \(\geq\) 4 + 3
y \(\geq\) 7
therefore p = {3, 4, 5, 6, 7} and Q = {7, 6, 5, 4, 3....}
P\(\cap\)Q = {3, 4, 5, 6, 7}