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(a) If \(\frac{3}{2p - \frac{1}{2}} = \frac{\frac{1}{3}}{\frac{1}{4}p + 1}\), find ...

(a) If \(\frac{3}{2p - \frac{1}{2}} = \frac{\frac{1}{3}}{\frac{1}{4}p + 1}\), find p.
(b) A television set was marked for sale at GH¢ 760.00 in order to make a profit of 20%. The television set was actually sold at a discount of 5%. Calculate, correct to 2 significant figures, the actual percentage profit.
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    Correct Answer: Option n
    Explanation:
    (a) \(\frac{3}{2p - \frac{1}{2}} = \frac{\frac{1}{3}}{\frac{1}{4}p + 1}\)
    \(\implies 3(\frac{1}{4}p + 1) = \frac{1}{3}(2p - \frac{1}{2})\)
    \(\frac{3}{4}p + 3 = \frac{2}{3}p - \frac{1}{6}\)
    \(\frac{3}{4}p - \frac{2}{3}p = - 3 - \frac{1}{6}\)
    \(\frac{1}{12}p = - 3\frac{1}{6}\)
    \(p = \frac{-19}{6} \div \frac{1}{12}\)
    \(p = \frac{-19}{6} \times 12 = -38\)
    (b) \(5% \times ¢760.00 = \frac{5}{100} \times ¢760 = ¢38.00\)
    So the TV set was actually sold for ¢(760 - 38) = ¢722.00
    Using,
    \(% profit = \frac{\text{SP - CP}}{CP} \times 100%\)
    \(20% = \frac{760 - x}{x} \times 100%\)
    \(20% x = (760 - x) \times 100%\)
    \(x = 5(760 - x) \implies x = 3800 - 5x\)
    \(6x = 3800 \implies x = ¢633.33\)
    Thus, the actual profit = actual SP - CP
    = ¢(722 - 633.33)
    = ¢88.67
    Hence, actual %age profit = \(\frac{88.67}{633.33} \times 100%\)
    = 14.0006%
    = 14% (2 sig. figs)

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