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Make s the subject of the relation: P = S + \(\frac{sm^2}{nr}\)

Make s the subject of the relation: P = S + \(\frac{sm^2}{nr}\)
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  • A S = \(\frac{mrp}{nr + m^2}\)
  • B S = \(\frac{nr + m^2}{mrp}\)
  • C S = \(\frac{nrp}{mr + m^2}\)
  • D S = \(\frac{nrp}{nr + m^2}\)
Correct Answer: Option D
Explanation:
P = S + \(\frac{sm^2}{nr}\)
P = S(1 + \(\frac{m^2}{nr}\))
P = S(1 + \(\frac{nr + m^2}{nr}\))
nrp = S(nr + m2)
S = \(\frac{nrp}{nr + m^2}\)

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