In the diagram, \(\bar{PF}\), \(\bar{QT}\), \(\bar{RG}\) intersect at S and PG||RG. If < SPQ = 113o and < RSt = 220, find < PSQ
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Correct Answer: Option B
Explanation:
In In the diagram given, \(\alpha\) = 22o (vertically opp. angles), \(\alpha\) = \(\beta\) (alternate angles)
< PSQ + 133o + \(\beta\) = 180o (sum of angles of a \(\Delta\))
< PSQ + 133o + 22o = 180o
< PSQ = 180o - (133 + 22)o
45o
In In the diagram given, \(\alpha\) = 22o (vertically opp. angles), \(\alpha\) = \(\beta\) (alternate angles)
< PSQ + 133o + \(\beta\) = 180o (sum of angles of a \(\Delta\))
< PSQ + 133o + 22o = 180o
< PSQ = 180o - (133 + 22)o
45o