If log2(3x - 1) = 5, find x.
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Correct Answer: Option D
Explanation:
Log2(3x - 1) = 5
Log2(3x - 1) = Log225
Log2(3x - 1) = Log232
3x - 1 = 32
3x = 32 + 1 = 33
x = \(\frac{33}{3}\)
= 11
Log2(3x - 1) = 5
Log2(3x - 1) = Log225
Log2(3x - 1) = Log232
3x - 1 = 32
3x = 32 + 1 = 33
x = \(\frac{33}{3}\)
= 11