Out of 120 customers in a shop, 45 bought both bags and shoes. If all the customers bought either bags or shoes and 11 more customers bought shoes than bags:
(a) Illustrate the this information in a diagram;
(b) find the number of customers who bought shoes;
(c) calculate the probability that a customer selected at random bought bags.
(a) Illustrate the this information in a diagram;
(b) find the number of customers who bought shoes;
(c) calculate the probability that a customer selected at random bought bags.
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Correct Answer: Option n
Explanation:
(a)
(b) \(x + 45 + x + 11 = 120 \implies 2x + 56 = 120\)
\(2x = 120 - 56 = 64\)
\(x = 32\)
Therefore, the number of customers that bought bags = 32.
(c) \(P(\text{a random customer bought bags}) = \frac{\text{no of customers that bought bags}}{\text{total no of customers}}\)
No of customers that bought bags = 32 + 45 = 77
\(P(\text{customer bought bag}) = \frac{77}{120}\).
(a)
(b) \(x + 45 + x + 11 = 120 \implies 2x + 56 = 120\)
\(2x = 120 - 56 = 64\)
\(x = 32\)
Therefore, the number of customers that bought bags = 32.
(c) \(P(\text{a random customer bought bags}) = \frac{\text{no of customers that bought bags}}{\text{total no of customers}}\)
No of customers that bought bags = 32 + 45 = 77
\(P(\text{customer bought bag}) = \frac{77}{120}\).