Solve for t in the equation \(\frac{3}{4}\)t + \(\frac{1}{3}\)(21 - t) = 11
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Correct Answer: Option D
Explanation:
\(\frac{3}{4}\) t + \(\frac{1}{3}\) (21 - t) = 11
 Multiply through by the LCM of 4 and 3 which is 12
 12 x(\(\frac{3}{4}\) t) + 12 x (\(\frac{1}{3}\) (21 - t)) = (11 x 12)
 9t + 4(21 - t) = 132
 9t + 84 - 4t = 132
 5t + 84 = 132
 5t = 132 - 84 = 48
 t = \(\frac{48}{5}\)
 t = 9 \(\frac{3}{5}\)
 Answer is D
\(\frac{3}{4}\) t + \(\frac{1}{3}\) (21 - t) = 11
 Multiply through by the LCM of 4 and 3 which is 12
 12 x(\(\frac{3}{4}\) t) + 12 x (\(\frac{1}{3}\) (21 - t)) = (11 x 12)
 9t + 4(21 - t) = 132
 9t + 84 - 4t = 132
 5t + 84 = 132
 5t = 132 - 84 = 48
 t = \(\frac{48}{5}\)
 t = 9 \(\frac{3}{5}\)
 Answer is D