The first and last term of a linear sequence (AP) are 6 and 10 respectively. If the sum of the sequence is 40. Find the number of terms
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
nth term of a linear sequence (AP) = a+(n − 1)d
first term = 6, last term = 10 sum − 40
i.e. a = 6, l = 10, S = 40
S\(_{n}\)= n/2(2a + (n − 1)d or Sn = ÷2 (a + l)
S\(_{n}\)Â = n/2(a + l)
40 = n/2(6 + 10)
40 = 8n
8n = 40
8n = 40
n = 40/8
= 5
The number of terms = 5
nth term of a linear sequence (AP) = a+(n − 1)d
first term = 6, last term = 10 sum − 40
i.e. a = 6, l = 10, S = 40
S\(_{n}\)= n/2(2a + (n − 1)d or Sn = ÷2 (a + l)
S\(_{n}\)Â = n/2(a + l)
40 = n/2(6 + 10)
40 = 8n
8n = 40
8n = 40
n = 40/8
= 5
The number of terms = 5