Explanation:
Convert the binary to base 10 and they convert back to base two
10011₂ + xxxxx₂ + 11100₂ + 101₂ = 1001111₂
(1 × 2⁴ + 0 × 2³ + 1 × 2² + 1 × 2¹ + 1 × 2⁰) + xxxxx₂ +(1 × 2⁴ + 1 × 2³ + 1 × 2² + 0 × 2¹ + 0 × 2⁰) + (1 × 2² + 0 × 2¹ + 1 × 2⁰)
= (16 + 0 + 0 + 2 + 1) + xxxxx₂ + (16 + 8 + 4 + 0 + 0 ) + (4 + 0 + 1)
=(64 + 0 + 0 + 8 + 4 + 2 + 1)
19 + xxxxx₂ + 33 = 79
xxxxx₂ + 52 = 79
xxxxx₂ = 79 − 52
xxxxx₂ = 27₁₀
\( \begin{array}{c|c}
2 & 27 \\
\hline
2 & 13 \text{ rem 1}\\
2 & 6 \text{ rem 1}\\
2 & 3 \text{ rem 0}\\
2 & 1 \text{ rem 1}\\
& 0 \text{ rem 1}\\
\end{array}\uparrow \)
27₁₀ = 11011₂
Therefore xxxxx₂ = 27₁₀ = 11011₂