A cylindrical tank has a capacity of 6160m3. What is the depth of the tank if the radius of its base is 28cm?
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Correct Answer: Option D
Explanation:
Using \(V = \pi r^2 h\)
6160 = 22/7 x 28 x 28 x h
\(h = \frac{6160}{22 \times 4 \times 28} \)
\(h = 2.5m \)
Using \(V = \pi r^2 h\)
6160 = 22/7 x 28 x 28 x h
\(h = \frac{6160}{22 \times 4 \times 28} \)
\(h = 2.5m \)