The nth term of the progression \(\frac{4}{2}\), \(\frac{7}{3}\), \(\frac{10}{4}\), \(\frac{13}{5}\) is ...
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Correct Answer: Option B
Explanation:
Using Tn = \(\frac{3n + 1}{n + 1}\),
T1 = \(\frac{3(1) + 1}{(1) + 1} = \frac{4}{2}\)
T2 = \(\frac{3(2) + 1}{(2) + 1} = \frac{7}{3}\)
T3 = \(\frac{3(3) + 1}{(3) + 1} = \frac{10}{4}\)
Using Tn = \(\frac{3n + 1}{n + 1}\),
T1 = \(\frac{3(1) + 1}{(1) + 1} = \frac{4}{2}\)
T2 = \(\frac{3(2) + 1}{(2) + 1} = \frac{7}{3}\)
T3 = \(\frac{3(3) + 1}{(3) + 1} = \frac{10}{4}\)