In the diagram given, find the value of x.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
In the diagram above, < CDE = < CED = 15o
(base < s of isos. \(\bigtriangleup\))
< ECD = 180o - (15 + 15)o
= 180o - 30o = 150o
But x + 110o = 150o
(Sum of opp. interior < s of a\(\bigtriangleup\) = opp. exterior < )
x = 150o - 110o = 40o
In the diagram above, < CDE = < CED = 15o
(base < s of isos. \(\bigtriangleup\))
< ECD = 180o - (15 + 15)o
= 180o - 30o = 150o
But x + 110o = 150o
(Sum of opp. interior < s of a\(\bigtriangleup\) = opp. exterior < )
x = 150o - 110o = 40o