Find the length of a chord which subtends an angle of 90° at the centre of a circle whose radius is 8 cm.
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Correct Answer: Option D
Explanation:
Length of chord = \(2r \sin (\frac{\theta}{2})\)
= \(2 \times 8 \times \sin (\frac{90}{2})\)
= \(16 \times \frac{\sqrt{2}}{2}\)
= \(8\sqrt{2} cm\)
Length of chord = \(2r \sin (\frac{\theta}{2})\)
= \(2 \times 8 \times \sin (\frac{90}{2})\)
= \(16 \times \frac{\sqrt{2}}{2}\)
= \(8\sqrt{2} cm\)