If the midpoint of the line PQ is (2,3) and the point P is (-2, 1), find the coordinate of the point Q.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
Midpoint of a line PQ where P has coordinates (x\(_{1}\), y\(_{1}\)) and Q has coordinates (x\(_{2}\), y\(_{2}\)) is given asÂ
\((\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})\).
\(\therefore\) If Q has coordinates (r, s), then
\(\frac{-2 + r}{2} = 2\) and \(\frac{1Â + s}{2} = 3\)
\(-2 + r = 4 \implies r = 6\)
\(1 + s = 6 \implies s = 5\)
Q = (6, 5)
Midpoint of a line PQ where P has coordinates (x\(_{1}\), y\(_{1}\)) and Q has coordinates (x\(_{2}\), y\(_{2}\)) is given asÂ
\((\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})\).
\(\therefore\) If Q has coordinates (r, s), then
\(\frac{-2 + r}{2} = 2\) and \(\frac{1Â + s}{2} = 3\)
\(-2 + r = 4 \implies r = 6\)
\(1 + s = 6 \implies s = 5\)
Q = (6, 5)